0=16(-x^2+4+5)

Solution for 0=16(-x^2+4+5) equation:

0=16(-x^2+4+5)

We move all terms to the left:

0-(16(-x^2+4+5))=0

We add all the numbers together, and all the variables

-(16(-x^2+4+5))=0


We calculate terms in parentheses: -(16(-x^2+4+5)), so:

16(-x^2+4+5)

We multiply parentheses

-16x^2+64+80

We add all the numbers together, and all the variables

-16x^2+144

Back to the equation:

-(-16x^2+144)


We get rid of parentheses

16x^2-144=0

a = 16; b = 0; c = -144;
Δ = b2-4ac
Δ = 02-4·16·(-144)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-96}{2*16}=\frac{-96}{32}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+96}{2*16}=\frac{96}{32}
=3
$